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CTET 7 Feb 2026 Paper 1, Question 36

Topic: Numbers

Q36

(LCM of 96, 120 and 160) ÷\div (HCF of 72 and 168) is equal to

  1. (1) 12
  2. (2) 15
  3. (3) 20Correct answer
  4. (4) 30

Solution.

CBSE answer: (3)

Answer: (3) 20

  1. 96=25×396 = 2^5 \times 3, 120=23×3×5120 = 2^3 \times 3 \times 5, 160=25×5160 = 2^5 \times 5.
  2. LCM takes the highest powers: 25×3×5=4802^5 \times 3 \times 5 = 480.
  3. 72=23×3272 = 2^3 \times 3^2, 168=23×3×7168 = 2^3 \times 3 \times 7, so HCF =23×3=24= 2^3 \times 3 = 24.
  4. 480÷24=20480 \div 24 = 20.