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NDA 2 2025 Maths, question 38

Topic: Algebra

Passage · Q37 to Q38

Let f(x)=ax2+bx+cf(x)=ax^{2}+bx+c be a quadratic polynomial such that f(1)=f(4)=2f(1)=f(4)=2. Further, 22 is a root of f(x)=0f(x)=0.

Q38

What is (a+b+c)(a+b+c) equal to?

  1. (a) 00
  2. (b) 11
  3. (c) 22Correct answer
  4. (d) Cannot be determined

Solution.

Answer: (c) 22

  1. By definition, a+b+c=f(1).
  2. The question directly gives f(1)=2, so no coefficient calculation is needed.