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NDA 2 2025 Maths, question 37

Topic: Algebra

Passage · Q37 to Q38

Let f(x)=ax2+bx+cf(x)=ax^{2}+bx+c be a quadratic polynomial such that f(1)=f(4)=2f(1)=f(4)=2. Further, 22 is a root of f(x)=0f(x)=0.

Q37

What is the other root of f(x)=0f(x)=0?

  1. (a) 11
  2. (b) 22
  3. (c) 33Correct answer
  4. (d) Cannot be determined

Solution.

Answer: (c) 33

  1. Equal values f(1)=f(4) place the axis at x=(1+4)/2=5/2.
  2. The two roots are symmetric about this axis, so their sum is 5.
  3. Since one root is 2, the other is 3.
  4. Checking f(x)=(x−2)(x−3) satisfies the given values.