Q64If a line x+1p=y−1q=z−2r\frac{x + 1}{p} = \frac{y - 1}{q} = \frac{z - 2}{r}px+1=qy−1=rz−2, where p=2q=3rp = 2q = 3rp=2q=3r, makes an angle θ\thetaθ with the positive direction of yyy-axis, then what is cos2θ\cos 2\thetacos2θ equal to? a(a) −31/49- 31/49−31/49Correct answerb(b) −37/49- 37/49−37/49c(c) 31/4931/4931/49d(d) 37/4937/4937/49