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CTET 8 Feb 2026 Paper 1, Question 89

Topic: Travel and transport

Q89

A person boarded Rajdhani train from New Delhi on 30 April 2022 and reached Bhubaneshwar on 01 May 2022. The train departed from New Delhi at 17:00 hours and reached Bhubaneshwar at 20:00 hrs on 01 May 2022. If the distance between New Delhi and Bhubaneshwar by train route is nearly 1701 km. The average speed of the train during this journey was :

  1. (1) 62.7 km/h
  2. (2) 63 km/hCorrect answer
  3. (3) 63.3 km/h
  4. (4) 60 km/h

Solution.

CBSE answer: (2)

Answer: (2) 63 km/h

  1. 17:00 on 30 April to 17:00 on 1 May is 24 hours; to 20:00 adds 3 hours. Total 27 hours.
  2. Average speed =1701÷27=63= 1701 \div 27 = 63 km/h.
  3. Check: 27×63=170127 \times 63 = 1701.

Trap: (4) 60 km/h is just a round figure; (1) and (3) come from miscounting the hours.