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CTET 1 Mar 2026 Paper 1, Question 33

Topic: Operations on numbers

Q33

If 1001×121=11×12111−275×1001 \times 121 = 11 \times 12111 - 275 \times ___________, then what is the number at the blank space ?

  1. (1) 42
  2. (2) 88
  3. (3) 44Correct answer
  4. (4) 22

Solution.

CBSE answer: (3)

Answer: (3) 44

  1. 1001×121=1211211001 \times 121 = 121121 and 11×12111=13322111 \times 12111 = 133221.
  2. So 275×□=133221−121121=12100275 \times \square = 133221 - 121121 = 12100.
  3. □=12100÷275=44\square = 12100 \div 275 = 44.
  4. Check: 275×44=12100275 \times 44 = 12100, so the equation balances on both sides.