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UPSC Prelims 2025 CSAT, question 60

Topic: Series and patterns

Q60

What is XX in the sequence

1,3,6,11,18,X,421,3,6,11,18,X,42 ?

  1. (a) 26
  2. (b) 27
  3. (c) 29Correct answer
  4. (d) 30

Solution.

Answer: (c) 29

  1. The differences between consecutive terms of 1,3,6,11,18,X,421, 3, 6, 11, 18, X, 42 start with 3−1=23 - 1 = 2, 6−3=36 - 3 = 3, 11−6=511 - 6 = 5, and 18−11=718 - 11 = 7, which are consecutive prime numbers.
  2. Adding the next two primes 1111 and 1313 gives X=18+11=29X = 18 + 11 = 29 and 29+13=4229 + 13 = 42.