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NDA 2 2025 Maths, question 85

Topic: Integral calculus

Passage · Q85 to Q86

Let u=∫excos⁡xdxu=\int e^{x}\cos x dx and v=∫exsin⁡xdxv=\int e^{x}\sin x dx.

Q85

What is u+vu+v equal to?

  1. (a) −dudx-\frac{du}{dx}
  2. (b) −dvdx-\frac{dv}{dx}
  3. (c) dudx\frac{du}{dx}
  4. (d) dvdx\frac{dv}{dx}Correct answer

Solution.

Answer: (d) dvdx\frac{dv}{dx}

  1. u=ex(sin⁡x+cos⁡x)2u = \frac{e^{x}(\sin x + \cos x)}{2} and v=ex(sin⁡x−cos⁡x)2v = \frac{e^{x}(\sin x - \cos x)}{2}.
  2. Adding, u+v=exsin⁡xu + v = e^{x}\sin x.
  3. And dvdx=exsin⁡x\frac{dv}{dx} = e^{x}\sin x, so u+v=dvdxu + v = \frac{dv}{dx}.

Trap: Each integral carries a constant of integration; the equality holds when the constants are left out, as is standard.