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NDA 2 2025 Maths, question 52

Topic: Analytical geometry

Passage · Q51 to Q52

A plane PP is parallel to the line having direction ratios ⟨1,3,2⟩⟨1,3,2⟩ and contains the line of intersection of the planes 6x+4y−5z=26x+4y-5z=2 and x−2y+3z=0x-2y+3z=0.

Q52

What is the equation of the plane PP?

  1. (a) 2x−20y+29z+2=02x-20y+29z+2=0Correct answer
  2. (b) 2x−20y+29z−2=02x-20y+29z-2=0
  3. (c) 2x+3y+2z−4=02x+3y+2z-4=0
  4. (d) x−3y+2z+5=0x-3y+2z+5=0

Solution.

Answer: (a) 2x−20y+29z+2=02x-20y+29z+2=0

  1. A plane through the intersection is (6x+4y−5z−2)+λ(x−2y+3z)=0.
  2. Its normal dotted with (1,3,2) is 8+λ.
  3. Parallelism requires λ=−8, giving −2x+20y−29z−2=0, equivalent to option (a).