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NDA 1 2025 Maths, question 58

Topic: Analytical geometry

Q58

A tangent to the parabola y2=4xy^{2} = 4x is inclined at an angle 45∘45^{\circ} with the positive direction of xx-axis. What is the point of contact of the tangent and the parabola?

  1. (a) (1,1)(1,1)
  2. (b) (2,22)\left( 2,2\sqrt{2} \right)
  3. (c) (1/2,1/2)\left( 1/2,1/\sqrt{2} \right)
  4. (d) (1,2)(1,2)Correct answer

Solution.

Answer: (d) (1,2)(1,2)

  1. The required tangent slope is tan⁡45∘=1\tan 45^{\circ} = 1.
  2. Differentiating y2=4xy^{2} = 4x gives dy/dx=2/ydy/dx = 2/y.
  3. Setting 2/y=12/y = 1 gives y=2y = 2, and then x=y2/4=1x = y^{2}/4 = 1.
  4. The point of contact is (1,2)(1,2).